Free Lean Six Sigma Black Belt Practice Exam (2026)
Full-length Black Belt mock exams with the same number of questions and time as common Black Belt certification exams. Define, Measure, Analyze, Improve and Control questions with real calculations, answers explained, and your score by phase.
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150 questions · 4 hours · same as the real exam
A call center Black Belt writes the project relationship as Y = f(x). Average handle time is the output, and agent experience, call type, and system response time are suspected drivers. Which statement BEST describes how the team should use this relationship?
The Y is an output, so it improves only when the critical inputs that drive it are identified and controlled. Adjusting the Y directly treats the symptom and ignores the causes.
A plant runs one 8-hour shift with two 15-minute breaks. Customer demand is 900 units per shift. What is the takt time?
Available time is 480 - 30 = 450 minutes, or 27,000 seconds, and takt = 27,000 / 900 = 30 seconds. The value 32 seconds forgets to subtract the breaks.
A Black Belt tests whether a new resin changes average tensile strength from the current 50 MPa. What is the null hypothesis?
The null hypothesis states no change, so the population mean equals 50 MPa. Hypotheses are always about population parameters, not sample statistics.
A regression model for weekly overtime hours at a distribution center is Overtime = 12 + 3.5 x (thousands of orders). What overtime does the model predict for a week with 8 thousand orders?
Overtime = 12 + 3.5 x 8 = 12 + 28 = 40.0 hours. The value 28.0 leaves out the intercept of 12.
A chemical plant measures the viscosity of each batch once, and a new batch is made about every four hours. Which control chart is MOST appropriate?
With one continuous measurement per batch and no natural subgroups, an individuals and moving range chart is used. Xbar-R needs several measurements per subgroup.
A team concludes that a new supplier's parts have a different mean diameter, but in truth there is no difference. What error was made?
A Type I error rejects a true null hypothesis, finding a difference that does not exist. A Type II error fails to detect a difference that really exists.
A value stream map for a permit office shows 30 minutes of total value-added time and a total lead time of 10 hours. What is the process cycle efficiency?
PCE = value-added time / lead time = 30 / 600 minutes = 0.05, or 5%. Lead time must be converted to minutes first, which is why 0.5% and 30% are wrong.
A regression of delivery time on number of stops has an R-squared of 0.72. What does this mean?
R-squared is the proportion of variation in the response explained by the model. The correlation would be the square root of 0.72, about 0.85, not 0.72.
A circuit board plant inspected 500 boards. Each board has 10 opportunities for a defect, and inspectors found 25 defects in total. What is the DPMO?
DPMO = defects / (units x opportunities) x 1,000,000 = 25 / (500 x 10) x 1,000,000 = 5,000. The value 50,000 comes from ignoring opportunities and using 25 / 500.
A machining cell measures 4 consecutive parts every hour for shaft diameter. Which control chart is MOST appropriate?
Small rational subgroups of continuous data, such as 4 parts, suit an Xbar and range chart. Attribute charts like np or u are for counts, not measurements.
A claims office has an average of 200 claims in process and completes 40 claims per day. Using Little's Law, what is the average lead time?
Little's Law states lead time = WIP / throughput = 200 / 40 = 5 days. The value 0.2 days inverts the ratio.
A seal integrity test on a drug packaging line fails to detect a real increase in seal failures, and the team concludes nothing has changed. What error occurred, and what is its main risk?
Failing to detect a real change is a Type II error, and its risk is that a true problem continues. Acting on a false alarm is the risk of a Type I error.
A claims process has three sequential steps with first pass yields of 95%, 90%, and 98%. What is the rolled throughput yield?
RTY is the product of the step yields: 0.95 x 0.90 x 0.98 = 0.838, or 83.8%. The value 94.3% is the simple average, which overstates the chance a unit passes every step without rework.
Adding a fourth predictor to a regression model raises R-squared from 0.810 to 0.812 but lowers adjusted R-squared from 0.795 to 0.788. What does this suggest?
R-squared never falls when a predictor is added, but adjusted R-squared penalizes terms that do not add real explanatory power. A drop in adjusted R-squared signals the new term is not worth keeping.
A high-speed filler samples 12 bottles per subgroup for fill volume. Which control chart is BEST for monitoring both center and spread?
For larger subgroups, usually above about 10, the standard deviation estimates spread better than the range, so Xbar-S is preferred. The range ignores most of the data in a large subgroup.
A glass plant records the number of surface blemishes found on each sheet. What type of data is this?
Counts of blemishes take whole number values, so they are discrete count data. Continuous data, such as thickness, can take any value within a range.
A hypothesis test is designed with beta = 0.20. What is the power of the test?
Power = 1 - beta = 1 - 0.20 = 0.80, the probability of detecting a real difference. The value 0.95 is 1 - alpha for a common alpha, which is a different quantity.
A hotel chain survey shows guests rarely mention clean towels, yet complaints spike sharply whenever towels are missing. In the Kano model, clean towels are BEST classified as which type of requirement?
Basic needs are expected and unspoken, so meeting them earns little credit but missing them causes strong dissatisfaction. A performance need would raise satisfaction steadily as it improves, which is not the pattern here.
A plot of residuals versus fitted values shows a funnel shape that widens as the fitted values increase. What does this indicate?
A widening funnel shows that error variance grows with the fitted value, which violates the equal variance assumption. A transformation or weighted regression may be needed.
A mail-order pharmacy tracks the proportion of prescriptions with errors each day, and daily volume varies widely. Which chart fits?
A p chart plots the proportion defective and handles varying sample sizes by adjusting the limits. An np chart needs a constant sample size.
A bank's call volume comes from three regions that differ greatly in size and customer mix. The Black Belt wants a sample that represents each region in proportion. Which sampling method is BEST?
Stratified sampling divides the population into groups and samples each one, so every region is properly represented. Simple random sampling could under-represent a small region by chance.
Using alpha = 0.05, a 2-sample t-test comparing the mean output of two machines returns p = 0.03. What is the correct conclusion?
Because p = 0.03 is below alpha = 0.05, the null hypothesis of equal means is rejected. A p-value is not the probability that either hypothesis is true.
Patients at an outpatient clinic say they want quick service. The Black Belt is building a CTQ tree from this comment. Which item is the BEST CTQ to place at the end of the branch?
A CTQ must be specific and measurable with a clear target, which turns vague VOC into a requirement the process can be judged against. Adding staff is a solution, not a requirement.
In a multiple regression model, two predictors have variance inflation factors of 12 and 14. What is the MOST likely issue?
VIF values above about 5 to 10 indicate that a predictor is highly correlated with other predictors, which makes coefficients unstable. VIF does not measure residual normality.
An inspector checks exactly 200 circuit boards per day and records the number of defective boards. Which chart fits?
An np chart plots the number of defective units when the sample size is constant. A c or u chart counts defects, not defective units.
Repair times at a service center are strongly right-skewed because a few jobs take several days. Which statistic BEST describes a typical repair time?
The median is resistant to extreme values, so it describes the typical case in skewed data. The mean is pulled toward the long tail and overstates a typical repair time.
A Black Belt compares average loan processing time between two independent branches. The data are continuous and roughly normal. Which test is MOST appropriate?
A 2-sample t-test compares the means of two independent groups with continuous data. A paired t-test needs matched observations on the same units.
A Black Belt is drafting the problem statement for a project charter at a regional distribution center. Which statement is MOST appropriate?
A good problem statement describes what, where, when, and how big, with data, and avoids assigning causes or solutions. The training statement assumes a root cause before any analysis.
A model of cure time was built from data with oven temperatures between 150 and 200 degrees. A manager wants to use it to predict cure time at 260 degrees. What is the main concern?
Extrapolating beyond the range of the data assumes the relationship holds where it was never observed. The process may behave very differently at 260 degrees.
A paper mill counts the number of flaws on each roll, and every roll is the same size. Which chart fits?
A c chart plots the count of defects per unit when the area of opportunity is constant. A p chart tracks the proportion of defective units.
Fill weights are normally distributed with a mean of 50 g and a standard deviation of 4 g. The upper specification limit is 58 g. About what percent of packages exceed the upper limit?
z = (58 - 50) / 4 = 2.0, and the area above z = 2 is about 2.3%. The value 5% is the two-tailed area beyond plus or minus 2 sigma, not the area above one limit.
Ten technicians each had their task time measured before and after a training course. Which test BEST compares the two sets of times?
Each technician provides both measurements, so the data are paired and the test should analyze the differences. A 2-sample t-test treats the groups as independent and loses power.
A Black Belt at an insurance company has a newly approved charter for claims processing delays. Team members disagree about where the process starts and where it ends. Which tool should the Black Belt use FIRST?
A SIPOC gives a high-level view of suppliers, inputs, process steps, outputs, and customers and sets the start and stop points of the scope. A detailed swimlane map comes later, once the boundaries are agreed.
A Black Belt plans a full factorial experiment with 4 factors at 2 levels each, replicated twice, with no center points. How many runs are required?
A 2^4 design has 16 runs, and two replicates give 16 x 2 = 32 runs. The value 16 is a single replicate.
A hospital tracks patient falls each month, and the number of patient-days varies widely from month to month. Which chart fits?
A u chart divides each count by its exposure, here patient-days, so months of different sizes are compared fairly. A c chart would mislead because busier months naturally have more falls.
For a normally distributed process, about what percent of output falls within plus or minus 2 standard deviations of the mean?
The empirical rule gives about 68.3% within 1 sigma, 95.4% within 2 sigma, and 99.7% within 3 sigma. So 68.3% applies to plus or minus 1 sigma, not 2.
A plant compares average yield across four production lines. The data are normal with similar variances. Which test is BEST?
One-way ANOVA compares three or more means in one test while holding the overall alpha. Running six t-tests inflates the chance of a false positive.
During stakeholder analysis, a Black Belt finds that the plant operations director has high influence over the project and is currently opposed to it. What is the BEST action?
High-influence stakeholders who resist need active, direct engagement so their concerns can be addressed early. A newsletter is suited to low-influence stakeholders and leaves the resistance in place.
A Black Belt runs a half fraction of a 5-factor, 2-level design without replication or center points. How many runs are needed?
A half fraction of 2^5 is 2^(5-1) = 16 runs. The full factorial would need 32 runs.
A Black Belt needs to detect small, sustained shifts of about 0.5 sigma in a well-controlled process. Which chart is MOST suitable?
EWMA and CUSUM charts accumulate information over time, which makes them sensitive to small persistent shifts. Standard Shewhart charts are better at catching large, sudden shifts.
A gage R&R study on a bore gauge shows the measurement system accounts for 35% of total study variation. What is the BEST conclusion?
Common guidelines treat under 10% as acceptable, 10% to 30% as possibly acceptable, and over 30% as unacceptable. At 35%, the gauge adds too much noise to make reliable decisions.
A Black Belt wants to know if defect type (scratch, dent, or crack) depends on shift (day or night). Which test fits?
Both variables are categorical, so a chi-square test of independence checks whether they are related. ANOVA needs a continuous response.
An appliance maker pays for technician visits to repair washing machines that are still under warranty. In a cost of poor quality analysis, these costs belong in which category?
External failure costs arise after the product reaches the customer, such as warranty repairs and returns. Internal failure costs, like scrap and rework, occur before shipment.
Which statement is true of a Resolution III fractional factorial design?
In a Resolution III design, main effects are confounded with two-factor interactions, so it is used mainly for screening. Main effects clear of two-factor interactions describes Resolution IV.
On an Xbar chart, a point falls outside the upper control limit, but every part in that subgroup is within specification. What should the team do?
Control limits show the voice of the process, so a point outside them signals a likely special cause even if parts meet the customer's specs. Ignoring it risks a later drift outside the specs.
In a gage R&R study, the measurement system variance is 4 and the total observed variance is 100. What are the percent contribution and the percent study variation for the measurement system?
Percent contribution uses variances: 4 / 100 = 4%. Percent study variation uses standard deviations: square root of 4 / square root of 100 = 2 / 10 = 20%.
Before comparing the variability of fill volume across three filler heads, the Black Belt finds the data are clearly not normal. Which test of variances is MOST appropriate?
Levene's test compares variances of two or more groups and is robust to non-normal data. Bartlett's test assumes normality, and the F-test handles only two groups.
A furniture plant built 200 chairs last week. Final audit found 40 defects spread across the chairs, and some chairs had more than one defect. What is the defects per unit?
DPU = total defects / total units = 40 / 200 = 0.20. The value 5.00 inverts the ratio, and 0.80 confuses DPU with a yield figure.
Why do analysts often code DOE factor levels as -1 and +1 before fitting a model?
Coding puts factors with different units on a common scale, so coefficient sizes can be compared and terms are less correlated. It does not replace randomization.
On a control chart, nine consecutive points fall above the centerline, but all are inside the control limits. What does this MOST likely indicate?
A long run on one side of the centerline is very unlikely by chance and signals a shift in the mean, even if no point is beyond the limits. Common cause variation would scatter points on both sides.
A gage R&R study reports 2 distinct categories. What does this mean for the measurement system?
The number of distinct categories shows how many groups of parts the system can reliably tell apart, and at least 5 is the usual guideline. With 2, the gauge acts like a go/no-go check.
Customer wait times at two independent stores are heavily skewed, and the samples are small. Which test BEST compares the central tendency of the two stores?
The Mann-Whitney test is a nonparametric test for two independent groups that does not assume normality. A t-test on small, skewed samples can give unreliable p-values.
A finance team spends six hours a month adding color charts and extra rounding checks to a variance report. Interviews show the only reader looks at a single total on the first page. Which of the 8 wastes does this BEST represent?
Overprocessing is doing more work or adding more features than the customer needs. Overproduction would mean making more output, or making it sooner, than the customer requires.
In a 2-level experiment, the average yield is 70% at the high level of temperature and 60% at the low level. What is the main effect of temperature?
Main effect = average at high level - average at low level = 70 - 60 = 10 points. The value 65 is the overall average, not an effect.
Two of three consecutive points on an Xbar chart fall between 2 and 3 sigma above the centerline. How should this be treated?
Two of three points beyond 2 sigma on the same side is a common sensitizing rule that signals a nonrandom pattern. Waiting for a point outside 3 sigma would miss early warnings.
A gage R&R study shows repeatability variation is much larger than reproducibility variation. Where should the team look FIRST?
Repeatability is equipment variation, the spread when one person measures the same part repeatedly. Large reproducibility would point to operator differences instead.
A Black Belt must compare medians across four groups, and the data contain several extreme outliers. Which nonparametric test is MOST robust to the outliers?
Mood's median test only counts values above or below the overall median, so extreme outliers have little effect. Kruskal-Wallis is more powerful in general but is more affected by outliers.
After removing unneeded items from a maintenance crib, a team outlines each tool on a shadow board and labels every bin with its contents. Which 5S step are they performing?
Set in order gives every needed item a defined, visible home so it is easy to find and return. Sort was the earlier step of removing items that are not needed.
An interaction plot for pressure and line speed shows lines that cross sharply. What does this mean?
Non-parallel or crossing lines show an interaction, so one factor's effect changes with the level of the other. Parallel lines would mean no interaction.
Six consecutive points on an individuals chart steadily increase. What does this pattern MOST likely indicate?
A steady run of increasing or decreasing points signals a trend, often caused by wear, fatigue, or gradual drift. Overadjustment tends to cause alternating up and down points.
An attribute agreement study of loan file reviewers gives a kappa of 0.45 when their ratings are compared with an expert standard. What is the BEST interpretation?
Kappa above about 0.9 is excellent, 0.7 to 0.9 is often acceptable, and below 0.7 needs improvement. A value of 0.45 shows agreement is not much better than chance would suggest.
An Anderson-Darling normality test on 50 cycle times returns p = 0.01. Using alpha = 0.05, what does this indicate?
The null hypothesis of a normality test is that the data are normal, so a p-value below alpha rejects normality. A high p-value would mean no evidence against normality.
Which activity in a mortgage approval process is value-added from the customer's point of view?
Value-added work changes the product or service in a way the customer cares about and will pay for, done right the first time. Re-keying, rechecking, and waiting add time and cost without adding value.
A Black Belt adds center points to a 2^3 factorial experiment. What is the MAIN benefit?
Center points test whether the response bends between the low and high settings, which a two-level design alone cannot reveal. They do not change the resolution or add true factor levels.
A p chart is planned for a process with an average defective rate of 1%, using subgroups of 50 units. Why is this a problem?
With n x p-bar = 50 x 0.01 = 0.5, most subgroups show zero defectives and the chart cannot detect changes well. Larger subgroups are needed for low defect rates.
A technician measures a 10.00 mm reference standard 20 times and gets an average reading of 10.15 mm. What is the bias of the gauge?
Bias = observed average - reference value = 10.15 - 10.00 = +0.15 mm. The sign is positive because the gauge reads high.
A Black Belt finds a strong correlation (r = 0.85) between hours of overtime and error rate in a records department. What is the BEST conclusion?
Correlation shows association, not cause, and a third factor such as workload may drive both. A designed test or deeper analysis is needed to prove causation.
Three weeks into a project, team members openly argue about roles and question the Black Belt's approach in meetings. Which team stage is this, and what is the BEST response?
Conflict over roles and direction marks the storming stage, and the leader should clarify roles and set ground rules to move the team forward. Stepping back as if the team were norming lets the conflict continue.
A DOE needs 16 runs, but only 8 can be done per day, and day-to-day differences are suspected. What should the Black Belt do?
Blocking assigns runs to days so the day effect can be separated from factor effects. Running all high levels on one day would confound the factor with the day.
Why should a subgroup for an Xbar-R chart usually be made of consecutive parts produced close together in time?
Rational subgroups keep within-subgroup variation to common causes, so special causes show up as differences between subgroups. Mixing shifts within a subgroup inflates the range and widens limits.
A scale reads accurately at 1 kg but reads 0.3 kg high at 20 kg. Which measurement system property is the problem?
Linearity is a change in bias across the operating range of the gauge. Stability is a change in bias over time, not across the range.
A simple linear regression of delivery time on distance gives an R-squared of 0.64 with a positive slope. What is the correlation coefficient?
In simple linear regression, r is the square root of R-squared with the sign of the slope: the square root of 0.64 is 0.80, and the slope is positive. The value 0.41 squares R-squared instead of taking the root.
A supervisor keeps delaying data collection for a Black Belt's project, saying the team is too busy. What should the Black Belt do FIRST?
Resistance often has a real cause, such as workload or fear of blame, so the first step is to understand it directly. Escalating first can harden resistance and damage the working relationship.
Why should the runs in a designed experiment be performed in random order?
Randomization spreads the effects of unknown lurking variables, such as warm-up or drift, across all runs. Without it, a time trend could be mistaken for a factor effect.
An Xbar-R chart uses subgroups of 5. The grand average is 50.0 and the average range is 4.0. With A2 = 0.577, what is the upper control limit for the Xbar chart?
UCL = grand average + A2 x R-bar = 50.0 + 0.577 x 4.0 = 50.0 + 2.31 = 52.31. The value 54.00 adds the full average range instead of A2 x R-bar.
How should a lab check the stability of a pH meter over time?
Stability is consistency over time, so repeated measurements of a known reference plotted on a control chart reveal drift. A single-day study measures repeatability and reproducibility, not stability.
A multi-vari study of shaft diameter shows small variation within each shaft and between consecutive shafts, but large differences from one hour to the next. Which family of variation dominates?
Large differences between time periods point to temporal variation, such as tool wear, temperature, or shift changes. Positional variation would show large differences within each part.
A Champion has four candidate projects. Which one is the BEST candidate for a Black Belt DMAIC project?
DMAIC suits chronic problems with significant cost, an unknown root cause, and data available to analyze. A known fix is a just-do-it item, not a DMAIC project.
After screening, a team believes the optimum lies inside the current factor region and the response is curved. Which design is MOST appropriate?
A central composite design adds axial and center points to a factorial so a quadratic model can map curvature and locate an optimum. Two-level screening designs cannot model curvature.
A p chart has an average proportion defective of 0.10 and a constant subgroup size of 100. What are the control limits?
Sigma = square root of (0.10 x 0.90 / 100) = 0.03, so the limits are 0.10 plus or minus 3 x 0.03, giving 0.19 and 0.01. The pair 0.13 and 0.07 uses 1 sigma instead of 3.
A machining process has specification limits of 90 and 110, and a within-subgroup standard deviation of 2.5. What is Cp?
Cp = (USL - LSL) / (6 sigma) = 20 / 15 = 1.33. Cp ignores centering and only compares the tolerance width with the process spread.
A team wants to organize brainstormed causes of late patient discharges into categories such as people, methods, and equipment. Which tool fits BEST?
A cause-and-effect, or fishbone, diagram sorts possible causes into categories to guide investigation. A Pareto chart ranks causes after they have been counted.
Midway through a project on invoice errors, a director asks the team to also fix vendor onboarding delays. What is the BEST way for the Black Belt to handle this request?
Scope changes should be judged against the agreed in and out of scope boundaries and decided with the Champion. Quietly adding work causes scope creep and delays the original goal.
A first-order model shows yield rises with both temperature and time, and the optimum appears to be well outside the current test region. What should the team do next?
The method of steepest ascent moves runs along the direction of greatest improvement until the response stops rising. Fitting curvature makes sense only once the region near the optimum is reached.
A c chart for scratches per panel has an average count of 9. What are the control limits?
For a c chart, sigma = square root of c-bar = 3, so UCL = 9 + 9 = 18 and LCL = 9 - 9 = 0. The pair 12 and 6 uses only 1 sigma.
A process has a mean of 104, USL of 110, LSL of 90, and a standard deviation of 2. What is Cpk?
Cpu = (110 - 104) / 6 = 1.00 and Cpl = (104 - 90) / 6 = 2.33, and Cpk is the smaller value, 1.00. The value 1.67 is Cp, which ignores that the mean is off center.
A team uses 5 Whys on a complex packaging defect with several interacting causes. What is the MAIN limitation of this approach here?
5 Whys is simple and useful, but it tends to follow a single chain of causes. Complex problems with interacting causes need tools such as fishbone diagrams and data analysis.
A hospital team is applying Lean thinking to its patient discharge process. Which step should the team take FIRST?
Lean thinking starts by defining value from the customer's view, then mapping the value stream, creating flow, establishing pull, and seeking perfection. Building flow before value is defined risks speeding up the wrong work.
In a Pugh matrix, what is the role of the datum?
Each alternative is rated better, worse, or the same as the datum for each criterion. The datum is a baseline for comparison, not the winning option.
When should control limits on an established chart be recalculated?
Limits should be recalculated only when the process has truly changed, such as after an improvement, and the new state is stable. Recalculating after every signal hides special causes.
A process has Cp = 1.8 and Cpk = 0.9. What is the BEST first improvement action?
A large gap between Cp and Cpk means the spread fits the tolerance but the mean is off center. Shifting the mean toward the target raises Cpk toward Cp.
A Pareto chart shows that 2 of 9 complaint categories account for 78% of all complaints. What should the team do next?
The Pareto principle directs effort to the vital few categories that drive most of the problem. Spreading effort across all nine dilutes the impact.
A warehouse receives most of its weekly orders on Monday, which causes heavy overtime early in the week and idle staff on Thursday and Friday. Which Lean concept BEST describes the underlying problem?
Mura is unevenness in workload or demand, which is the root issue here. The Monday overtime is muri, or overburden, but it is a result of the uneven demand.
Why should a Black Belt pilot a new scheduling process in one clinic before rolling it out to all twelve clinics?
A pilot tests the solution under real conditions on a small scale, so issues can be fixed before full rollout. It does not replace the control plan.
An operator adjusts the machine after every part, moving the setting up when a part measures high and down when it measures low, even though the process is stable. What is the likely result?
Adjusting a stable process in response to common cause variation, called tampering, adds variation. A stable process should be left alone unless a special cause appears.
What is the key difference between Cp and Pp?
Cp reflects short-term potential using within-subgroup variation, while Pp uses the overall long-term standard deviation. Neither index accounts for centering; Cpk and Ppk do.
A Black Belt suggests always using nonparametric tests to avoid checking assumptions. What is the main drawback of this approach?
When data meet parametric assumptions, tests such as the t-test detect real differences with smaller samples than their nonparametric versions. Nonparametric tests do not require normality, so that option is backwards.
Which responsibility BEST belongs to the project Champion rather than the Black Belt?
The Champion is a senior leader who sponsors the project, clears roadblocks, and provides resources. Leading analysis and choosing tests are Black Belt tasks.
In a SMED event, a team finds operators search for dies and fetch tools while the press is stopped. What is the FIRST improvement to make?
SMED first separates internal and external tasks, then converts internal work, such as fetching dies, to external work done while the machine runs. Larger batches hide the problem and add inventory.
Which set of items is MOST essential to include in a control plan for a critical characteristic?
A control plan defines how each key characteristic is measured, how often, by whom, and what to do when it goes out of control. Project history documents do not control the process.
A Black Belt is asked to report Cpk for a process whose control chart shows several points beyond the control limits. What should happen FIRST?
Capability indices predict future performance only if the process is stable. Deleting points hides the problem without removing the special causes.
With 50,000 transactions, a test shows a statistically significant difference of 0.2 seconds in average processing time between two servers. What should the Black Belt consider NEXT?
Very large samples can make tiny differences statistically significant, so practical significance must also be judged. Changing alpha to avoid a result is not good practice.
A plant reports 98% final yield. A Black Belt finds that operators quietly rework about 15% of units before they reach final inspection. Which concept does this illustrate?
The hidden factory is the unrecorded rework and correction that final yield figures do not show. First pass yield or RTY would reveal it, while final yield hides it.
A kanban loop has demand of 100 parts per hour, a replenishment lead time of 2 hours, a 10% safety factor, and 20 parts per container. How many kanban cards are needed?
Cards = demand x lead time x (1 + safety) / container size = 100 x 2 x 1.1 / 20 = 220 / 20 = 11. The value 10 leaves out the safety factor.
An operator sees a point beyond the control limit on a critical dimension. According to a good response plan, what should happen FIRST?
A response plan tells the operator exactly what to do, usually to contain affected product and escalate. Unplanned adjustments can make things worse.
Why do many practitioners add a 1.5 sigma shift when converting short-term capability to long-term defect rates?
The 1.5 sigma shift is a convention that assumes the process mean wanders over the long term, which raises the long-term defect rate. It is not a correction for measurement error or sample size.
A sample of 100 orders has a mean processing time of 50 minutes and a standard deviation of 10 minutes. What is the approximate 95% confidence interval for the mean?
Standard error = 10 / square root of 100 = 1, so the interval is 50 plus or minus 1.96 x 1, or 48.04 to 51.96. The range 30.4 to 69.6 uses the standard deviation instead of the standard error.
A car maker added rear-view cameras years ago and buyers were delighted. Today, buyers complain if a car lacks one. What does this show about the Kano model?
Customer expectations rise, so features that once delighted become expected basics. This is why Kano analysis needs to be repeated as markets change.
A line has 120 seconds of total work content spread over 4 stations, and the cycle time is set at 40 seconds. What is the line balance efficiency?
Balance efficiency = total work / (stations x cycle time) = 120 / (4 x 40) = 120 / 160 = 75%. The rest is idle time built into the line.
Which element is a core part of standard work?
Standard work defines the takt time, the best known sequence of steps, and the standard amount of work in process. It becomes the baseline for further improvement.
A process makes 10% defective parts, and defectives occur independently. If 5 parts are drawn at random, what is the probability that none of them is defective?
Using the binomial model, P(0 defectives) = 0.90 to the 5th power = 0.590, or about 59%. The value 50% subtracts 5 x 10% from 1, which is not how independent probabilities combine.
A one-way ANOVA comparing five suppliers gives p = 0.002. What should the Black Belt do next to find which suppliers differ?
ANOVA only shows that at least one mean differs, so a multiple comparison method identifies which pairs differ while controlling error rates. Ten separate t-tests inflate the overall Type I error.
A Black Belt's project frees 400 hours of staff time per year, but no headcount, overtime, or spending is reduced. How should finance classify this benefit?
Hard savings show up as a real reduction in spending on the financial statements. Freed time with no change in spending is capacity or cost avoidance, which is treated as soft savings.
A connector is redesigned with an asymmetric shape so it can only be plugged in the correct way. What type of mistake-proofing is this?
The contact method uses physical features such as shape or size to detect or block errors. The fixed-value method checks that a set number of actions or parts was completed.
A plant installs lights above each workstation that turn on when an operator needs help or the line has a problem. What is this visual tool called?
An andon is a visual or audio signal that alerts others to a problem in real time. Kanban signals material replenishment, not problems.
Two failure modes have the same RPN of 120. One is rated severity 10, occurrence 3, detection 4. The other is severity 4, occurrence 5, detection 6. What should the team do?
RPN can hide serious risks, so high severity items, especially those that affect safety, should be addressed regardless of RPN. Equal RPNs do not mean equal risk.
In a one-way ANOVA, the mean square between groups is 40 and the mean square within groups is 8. What is the F statistic?
F = MS between / MS within = 40 / 8 = 5.0. The value 0.2 inverts the ratio.
In an assembly cell, workers repeatedly walk 10 meters to a shared cabinet to pick up hand tools. Which waste is this?
Motion is unnecessary movement of people, such as walking, reaching, or searching. Transportation is the unnecessary movement of materials or products between steps.
Which statement BEST describes a pull system?
In a pull system, consumption downstream triggers replenishment upstream, which limits work in process. Producing to a forecast and pushing work forward describes a push system.
Which control method gives the STRONGEST protection against a recurring assembly error?
Mistake-proofing that physically prevents the error is the strongest control because it does not rely on memory or attention. Inspection only catches defects after they are made.
In a process FMEA, what does a detection rating of 2 usually mean?
Detection is scored so that a low number means the failure is likely to be caught. Occurrence and severity are separate ratings.
A pooled 2-sample t-test compares a group of 12 parts with a group of 10 parts. How many degrees of freedom does the test have?
For a pooled 2-sample t-test, df = n1 + n2 - 2 = 12 + 10 - 2 = 20. The value 22 forgets to subtract one degree of freedom for each group.
A project aims to cut average call handle time. Why should the Black Belt also track a secondary metric such as first call resolution?
A secondary or counterbalancing metric shows whether improving the primary metric causes harm elsewhere, such as rushed calls and repeat contacts. It does not replace the primary metric.
A Black Belt is leading a solution brainstorming session for reducing billing delays. Which guideline should be followed during idea generation?
Brainstorming works best when criticism is held back so people offer many ideas, which are evaluated later. Judging ideas immediately discourages participation.
At project handover, what is the MOST important outcome for the process owner?
Sustaining the gains depends on the process owner taking responsibility for monitoring and responding with the control plan. Relying on the Black Belt after closure is not sustainable.
A Black Belt starts a value stream mapping effort at a coffee roasting facility. What should the team do FIRST?
The current state map, built from direct observation and real data, is the basis for finding waste. Designing the future state first skips understanding of how the process actually runs.
In a chi-square test of independence, a cell has a row total of 60 and a column total of 50, and the grand total is 200. What is the expected count for that cell?
Expected count = row total x column total / grand total = 60 x 50 / 200 = 15. The expected counts are what the table would show if the variables were independent.
Which tool BEST helps a Black Belt make sure each stakeholder receives the right project updates, in the right format, at the right frequency?
A communication plan lists audiences, messages, channels, frequency, and owners. A control plan defines how a process is monitored after improvement, not how stakeholders are updated.
Before installing a new automated dispensing system in a pharmacy, what should the team do to anticipate how the new process could fail?
An FMEA on the proposed process finds risks before implementation so controls can be built in. Waiting for errors exposes patients to avoidable harm.
Which activity is typically part of formally closing a Six Sigma project?
Closure includes financial validation, documentation, lessons learned, and recognition. Removing control charts would undermine the sustained gains.
Which process map is BEST for showing handoffs between sales, credit, and shipping departments in an order process?
A swimlane, or cross-functional, map places each step in the lane of the department that does it, so handoffs are easy to see. A spaghetti diagram shows physical movement, not departmental handoffs.
A supplier claims a new coating reduces corrosion. Management cares only whether corrosion decreases. Which test setup is MOST appropriate?
When only one direction matters, a one-tailed test puts all of alpha in that tail and gives more power for that direction. A two-tailed test would also look for an increase that management does not care about.
A bank plans to launch a brand new mobile lending product. No process for it exists yet. Which approach is MOST appropriate?
DMADV is used to design a new product or process to meet customer needs. DMAIC improves an existing process with a measurable baseline, which does not exist here.
In a 2-level factorial analyzed in coded units, the coefficient for factor A is 4. What is the effect of factor A?
In coded units, the effect is twice the coefficient because the factor moves from -1 to +1, a change of 2 units: 2 x 4 = 8. The coefficient alone is half the effect.
A plant uses short daily audits in which supervisors, managers, and executives each check a few key process steps at different frequencies. What is this practice called?
Layered process audits have several levels of leadership verify that standards are followed, which builds discipline and sustains gains. Gage R&R studies assess measurement systems.
A part characteristic has a total tolerance of 0.20 mm. Using the common 10-to-1 rule, what is the coarsest gauge resolution that is acceptable?
The 10-to-1 rule says resolution should be one tenth of the tolerance or finer: 0.20 / 10 = 0.02 mm. A resolution of 0.002 mm would also work but is finer than required, so it is not the coarsest acceptable value.
A Black Belt lowers alpha from 0.05 to 0.01 while keeping the same sample size. What is the likely effect?
With a fixed sample size, lowering alpha makes it harder to reject the null, so the chance of missing a real effect rises. Reducing both risks at once requires a larger sample.
A team has brainstormed 30 project ideas, but two senior members dominate every discussion. Which technique BEST gives everyone equal input when ranking the ideas?
Nominal group technique has each member generate and rank ideas individually before the group combines scores, which limits the influence of dominant voices. Open debate lets the same people dominate.
A screening experiment with 7 factors is planned. Which principle supports expecting only a few factors to have large effects?
The sparsity of effects principle says most systems are driven by a few main effects and low-order interactions. This is why fractional screening designs work well.
A stable process produces too many defects because its common cause variation is too large. Whose action is MOST needed to reduce it?
Common cause variation is built into the system, so reducing it requires changes to equipment, methods, or materials, which management controls. Asking operators to try harder does not change the system.
Two shifts report very different on-time delivery rates for the same trucks. One shift counts a delivery as on time within 30 minutes and the other within 2 hours. What is MOST needed?
An operational definition states exactly how a characteristic is measured so everyone collects data the same way. More data collected under different definitions would still be inconsistent.
After running a one-way ANOVA, which check BEST verifies that its assumptions hold?
ANOVA assumes independent, roughly normal residuals with equal variance across groups, and residual plots check this. The p-value shows the test result, not whether its assumptions are met.
Last quarter a plant scrapped 1,200 units at $15 each and reworked 300 units at $5 each. Ignoring all other costs, what was the internal failure cost?
Scrap is 1,200 x $15 = $18,000 and rework is 300 x $5 = $1,500, so internal failure cost is $19,500. The value $18,000 counts scrap only and leaves out rework.
In a normal probability plot of standardized effects from an unreplicated factorial, how are the important effects identified?
Unimportant effects behave like random noise and lie along a straight line, while real effects stand out away from it. Effects on the line are consistent with noise.
What is the main difference between Phase I and Phase II use of control charts?
In Phase I, historical data are studied to remove special causes and set trial limits. In Phase II, those limits are used to monitor ongoing production.
Operators need a simple way to record the type and location of defects on a form as they occur during the shift. Which tool is BEST?
A check sheet is a structured form for tallying events by category or location in real time. A Pareto chart is built afterward from data like this.
A team voted that machine age is the top root cause of downtime. What should the Black Belt do before moving to the Improve phase?
Root causes must be verified with data before solutions are chosen, because team opinion can be wrong. Replacing machines based on a vote risks spending money on the wrong cause.
After customer interviews, a team has 120 sticky notes with verbatim comments. Which tool should they use to sort these comments into natural themes?
An affinity diagram groups large amounts of language data into related themes. A Pareto chart ranks categories by frequency but needs the categories to exist first.
A team plans to test temperature, then pressure, then time, changing one factor at a time while holding the others fixed. What is the main drawback?
One-factor-at-a-time testing misses interactions between factors and is less efficient than a factorial design. It can lead to a false optimum.
An I-MR chart has an average of 20.0 and an average moving range of 2.0. What is the upper control limit for the individuals chart?
UCL = X-bar + 2.66 x MR-bar = 20.0 + 2.66 x 2.0 = 25.32, which equals 20 + 3 x (2.0 / 1.128). The value 26.00 wrongly uses 3 x MR-bar.
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Original practice questions written by CertOcean in the style of the Lean Six Sigma Black Belt exam. They are not real exam questions. Lean Six Sigma Black Belt and Lean Six Sigma are trademarks of their owners. Real exam format: 150 questions · 4 hours · about 30 questions per DMAIC phase · common pass mark around 70%.